40%T, 5.0%C Acrylamide/Bis-Acrylamide Solution (19:1)Contains 380 g/L acrylamide and20 g/L bis-acrylamide in Ultra Pure WaterSterile-filteredDNase, RNase and protease-none detected
Catalog Number ML 002-04Storage Temperature 2~8°C
Product DescriptionAcrylamide/N,N`-methylenebisacrylamide (Acrylamide/bis- acrylamide) solution is an essential ingredient in making poly acrylamide gel, which is used in electrophoresis of protein or nucleic acid. In the present product, acrylamide and bis-acrylamide are pre-dissolved at various concentrations for customer convenience and safety. The gel matrix is formed by free radical polymerization of acrylamide and comonom
PrecautionsFor In Vitro Use Only
Product Name
Description
Cat. No.
Recommended Storage Temp.
Size
30% T, 5.0% C Acrylamide/Bis-Acrylamide Solution (19:1)
Contains 285 g/L acrylamide and 15 g/L bis-acrylamide in Ultra Pure WaterSterile-filteredDNase, RNase and protease-none detected
ML 002-01
Store at 2-8°C
500ML, 1L
30% T, 3.3% C Acrylamide/Bis-Acrylamide Solution (29:1)
Contains 290.1 g/L acrylamide and 9.9 g/L bis-acrylamide in Ultra Pure WaterSterile-filteredDNase, RNase and protease-none detected
ML 002-02
30% T, 2.6% C Acrylamide/Bis-Acrylamide Solution (37.5:1)
Contains 292.2 g/L acrylamide and 7.8 g/L bis-acrylamide in Ultra Pure WaterSterile-filteredDNase, RNase and protease-none detected
ML 002-03
100ML500ML1L
40% T, 5.0% C Acrylamide/Bis-Acrylamide Solution (19:1)
Contains 380 g/L acrylamide and 20 g/L bis-acrylamide in Ultra Pure WaterSterile-filteredDNase, RNase and protease-none detected
ML 002-04
40% T, 3.3% C Acrylamide/Bis-Acrylamide Solution (29:1)
Contains 386.8 g/L acrylamide and 13.2 g/L bis-acrylamide in Ultra Pure WaterSterile-filteredDNase, RNase and protease-none detected
ML 002-05
40% T, 2.6% C Acrylamide/Bis-Acrylamide Solution (37.5:1)
Contains 389.6 g/L acrylamide and 10.4 g/L bis-acrylamide in Ultra Pure WaterSterile-filteredDNase, RNase and protease-none detected
ML 002-06
500ML
* %T = {acrylamide (g) + bis-acrylamide (g)} / volume (ml) X 100%* %C = bis-acrylamide (g) / {acrylamide (g) + bis-acrylamide (g)} X 100%